These problems were sourced from UW Madison MATH 542 Fall 2023 in-class material

1. Show that for all . Use this to show that .

Proof. We see that \begin{align*}0\cdot m &= (0 + 0)\cdot m,\\ &=0\cdot m + 0\cdot m.\end{align*} Applying left or right cancellation by yields . Using this result, \begin{align*}0 &= 0\cdot m,\\ &= (1 + (-1))\cdot m,\\ &=1\cdot m + (-1)\cdot m,\\ &= m + (-1)\cdot m.\end{align*} So is the inverse of and consequently as desired.

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